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25x^2-30x-10=10
We move all terms to the left:
25x^2-30x-10-(10)=0
We add all the numbers together, and all the variables
25x^2-30x-20=0
a = 25; b = -30; c = -20;
Δ = b2-4ac
Δ = -302-4·25·(-20)
Δ = 2900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2900}=\sqrt{100*29}=\sqrt{100}*\sqrt{29}=10\sqrt{29}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-10\sqrt{29}}{2*25}=\frac{30-10\sqrt{29}}{50} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+10\sqrt{29}}{2*25}=\frac{30+10\sqrt{29}}{50} $
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